Question

What is the systematic name of compound B? (3) OH B (A) (R)-3-butyl-5-hexen-1-ol (B) (R)-4-butyl-1-hexen-6-ol (C) (S)-4-butyl-1-hexen-6-ol (D) (R)-3-allyl-1-heptanol (4) What is the major product of the following reaction? excess HC CI C (A) (B) (C) (D)

Answer 1

a oH MM clockwise so R Now choose longest Carbon chain as functional group is - on so # so nome (0)- (R-3-allye-1-heptanal @ BY Acc to mar konikoon's rule part which is ce will go where less during no of Addition are ķ are there CH3 0 c=c-H ехсоло яс, excess Hal — (D) Producto
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od direction, the b d travels in a clockwise or righ The Conversion rule' says that : (1) If the eye while moving from a configuration is designated R (Latin. Rectus = right) left-hand direction, the (i) If the eye while moving from a b →d travels in counter clockwise or left-han configuration is designated S (Latin, Sinister = left) d R b S The sequence Rules to determine the order of priorities of groups are (0) The atoms or group directly bonded to the asymmetric carbon are arranged in order of decreasino atomic number and assigned priority 1,2,3,4, accordingly. Thus in chlorobromofluoromethane (CHCIBrF), the substituents Br (at no = 35), CI (at no = 17). F(at no = 9) and H (at no 1) given the order of priorties. Br > C > F > H (1) (2) (3) (4) () When two or more groups have identical first atoms attached to asymmetric carbon, the priority order is determined by considering the atomic numbers of the second atoms; and if the second atoms are also identical the third atoms along the chain are examined. Let us consider the three groups 1 2 - CH₂ - H methyl 1 2 3 CH₂ - CH₂ -H 1 2 3 CH2 - CH2 - CH3 ethyl n-propy! Self-Instruction

In methyl and ethyl the first atom is carbon and therefore, atomic n II (at no 1) and (at no 6) decide the priority order, ethyl > me n-propyl the second atom is also identical (carbon) and hence the order n-propyl > ethyl. efore, atomic numbers of the second atoms order, ethyl > methyl. While considering ethyl and arbon) and hence the third atoms (H, C) give the priority ime substituents of higher atomic number, the one (iii) If the first atoms of the two groups have same substituents of higher and with more substituents takes priority. Thus - CHCI2 has a higher priority than - CH2CH (iv) A doubly or triply bonded atom 'A' present in a group appended to asymm considered equivalent to two or three singly bonded 'A's, respectively. Thus = A equals (A, A) A = A equals A (A, A, A) Hence between groups -ċ = 0 (O, O, H) and — CH2OH (O, H, H), the former will have higher priority. A phenyl group is handled as if it had one of the Kekule structures. A A -