Question

Given: a mass (50) kg is on the edge of a rough horizontal turntable with radius...

Given: a mass (50) kg is on the edge of a rough horizontal turntable with radius R = 2.00 m Friction coefficients between the mass and the table are μs = 0.50 and μk = 0.40. The table starts to rotate (rotate) around the vertical axis of symmetry with a constant angular acceleration α = 0.60 rad / s2.

It has been asked to calculate the time at which the mass just will not shift. Can you help me further?

0 0
Add a comment Improve this question Transcribed image text
Answer #1

q-accelaration due to. 2 丈= LO 2

please rate it up thanks :)

Add a comment
Know the answer?
Add Answer to:
Given: a mass (50) kg is on the edge of a rough horizontal turntable with radius...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Given: a mass (50) kg is on the edge of a rough horizontal turntable with radius...

    Given: a mass (50) kg is on the edge of a rough horizontal turntable with radius R = 2.00 m Friction coefficients between the mass and the table are μs = 0.50 and μk = 0.40. The table starts to rotate (rotate) around the vertical axis of symmetry with a constant angular acceleration α = 0.60 rad / s2. It has been asked to calculate the speed v* on which the mass just will not shift. We must use a...

  • Given: a mass (50) kg is on the edge of a rough horizontal turntable with radius...

    Given: a mass (50) kg is on the edge of a rough horizontal turntable with radius R = 2.00 m Friction coefficients between the mass and the table are μs = 0.50 and μk = 0.40. The table starts to rotate (rotate) around the vertical axis of symmetry with a constant angular acceleration α = 0.60 rad / s2. It has been asked to calculate the specific time t* at which the mass just will not shift. We must use...

  • Given: a mass (50) kg is on the edge of a rough horizontal turntable with radius...

    Given: a mass (50) kg is on the edge of a rough horizontal turntable with radius R = 2.00 m Friction coefficients between the mass and the table are μs = 0.50 and μk = 0.40. The table starts to rotate (rotate) around the vertical axis of symmetry with a constant angular acceleration α = 0.60 rad / s2. It has been requested to calculate the labour that has delivered the frictional force from the start to the time t*...

  • Given: a mass (50) kg is on the edge of a rough horizontal turntable with radius...

    Given: a mass (50) kg is on the edge of a rough horizontal turntable with radius R = 2.00 m Friction coefficients between the mass and the table are μs = 0.50 and μk = 0.40. The table starts to rotate (rotate) around the vertical axis of symmetry with a constant angular acceleration α = 0.60 rad / s2. It has been requested to determine the distance (measured according to the track) that the mass has covered at the time...

  • Given: a mass (50) kg is on the edge of a rough horizontal turntable with radius...

    Given: a mass (50) kg is on the edge of a rough horizontal turntable with radius R = 2.00 m Friction coefficients between the mass and the table are μs = 0.50 and μk = 0.40. The table starts to rotate (rotate) around the vertical axis of symmetry with a constant angular acceleration α = 0.60 rad / s2. It has been requested to calculate the work of the frictional force from the start to the time t* (the point...

  • A 55.0-kg woman stands at the rim of a horizontal turntable having a moment of inertia of 540 kg · m2 and a radius of...

    A 55.0-kg woman stands at the rim of a horizontal turntable having a moment of inertia of 540 kg · m2 and a radius of 2.00 m. The turntable is initially at rest and is free to rotate about a frictionless vertical axle through its center. The woman then starts walking around the rim clockwise (as viewed from above the system) at a constant speed of 1.50 m/s relative to the Earth. (a) In what direction does the turntable rotate?...

  • A 65.0-kg woman stands at the rim of a horizontal turntable having a moment of inertia...

    A 65.0-kg woman stands at the rim of a horizontal turntable having a moment of inertia of 480 kg middot m^2 and a radius of 2.00 m. The turntable is initially at rest and is free to rotate about a frictionless vertical axle through its center. The woman then starts walking around the rim clockwise (as viewed from above the system) at a constant speed of 1.50 m/s relative to the Earth. (a) In what direction does the turntable rotate?...

  • A 65.0-kg woman stands at the rim of a horizontal turntable having a moment of inertia...

    A 65.0-kg woman stands at the rim of a horizontal turntable having a moment of inertia of 460 kg · m2 and a radius of 2.00 m. The turntable is initially at rest and is free to rotate about a frictionless vertical axle through its center. The woman then starts walking around the rim clockwise (as viewed from above the system) at a constant speed of 1.50 m/s relative to the Earth. (a) With what angular speed does the turntable...

  • A 64.0-kg woman stands at the western rim of a horizontal turntable having a moment of...

    A 64.0-kg woman stands at the western rim of a horizontal turntable having a moment of inertia of 495 kg .m2 and a radius of 2.00 m. The turntable is initially at rest and is free to rotate about a frictionless, vertical axle through its center. The woman then starts walking around the rim clockwise (as viewed from above the system) at a constant speed of 1.50 m/s relative to the Earth. Consider the woman-turntable system as motion begins. (a)...

  • Problem 3 A 60.0-kgrunner runs clockwise around the edge of a horizontal turntable mounted on a...

    Problem 3 A 60.0-kgrunner runs clockwise around the edge of a horizontal turntable mounted on a vertical, frictionless axis through its center. The runner's velocity relative to the ground has magnitude 2.00 m/s. The turntable is rotating in the opposite direction (counterclockwise) with an angular velocity of magnitude 0.300 rad/s relative to the ground. The radius of the turntable is 2.90 m, and its moment of inertia about the axis of rotation is 80.0 kg m2. Questions 4 and 5...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT