Question

Answer all the questions. Show all calculations in the space provided for full credit No credit will be given for answers only. Select the single correct response for questions 1-30 (2 points each) 1. Which figure below illustrates an s atomic orbital? (1) (2) (1) 10 (2) 2 (3) 3 (4) 4 . Which if any, is the ground-state electron configuration for Fe2 12) TAr 3d or 1s 2s 2p 3s%3p 3d (3) [Ar]3d" or 1s 2s 2p 3s 3p 3dº (1) TAT3 1 25204313 (4) (Ar]3d or 181220133 3 3. Which one of the following sets of quantum numbers is not possible? no . n 1 mm, 1. 4 3 -2 +² 2. 3 2 -3 3. 3 0 4. 4 1 1 -Oos (1)4 (2)3 (3) 2 (4) 4. Which one of the following sets of quantum numbers represents an electron with the highest energy! (1) n=2. = 1, m = 0, me = % (2) n = 3,7 = 2, m, 0, m h (3) n = 4.10 m m . (4) n = 2. ( = 1, m, = 1, m, = -2 5. What is the maximum number of electrons in an atom that can have the following quantum numbers ne and {=0? (1) 10 (2) 6 3 (4)2

Answer 1

1.

S orbital is spherical. Hence option 2 is correct.

2.

Number of electrons in Fe²⁺ = 26 -2 = 24

Hence, Electronic configuration of Fe²⁺ is

[Ar]3d⁶ or 1s²2s²2p⁶3s²3p⁶3d⁶ .

Option 4 is correct.

3.

value n is any integer.

Value of l is 0 to n-1 .

Value of m_l is - l to + l .

For each Value m_l the value of s are +$\frac{1}{2}$ , -$\frac{1}{2}$  .

In option 2, l = 2 , m_l = - 3 . Hence it is not correct.

Set 2 is not possible.

So option 3 is correct answer.

4.

Energy of orbitals increases with n+l value.

1)

n+l = 2+1= 3

2)

n+l = 3+2= 5.

3)

n+l = 4+0= 4

4)

n+l = 2+1= 3.

Hence, set 2 has highest energy.

Option (2) is correct.

5.

n = 3, l = 0, hence the orbital is 3s. Electron capacity of s orbital is 2.

Option 4 is correct.