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help with algorithm problems

just answer part A

Compare the texts implementation of insertion sort with the following version 8. ALGORITHM InsertSort2(A[0..n - 1]) for i1 t

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Answer #1

The for loop runs (n-1) times, for all the three cases

n-1 Σ1)-n-1 1

Best case: (when the array is already sorted)

It doesn't run the while loop even once.

Therefore, Best case time effeciency = \Omega \left ( n \right )

Average case

While loop runs on the average of (n-2)/2 times.

Therefore, Time complexity = (n-1)(n-2)/2 = e (n

Worst case: (when the loop is sorted in the reverse order i.e ascending instead of descending or vice versa)

While loop runs (n-2) times.

Therefore, Time complexity = (n-1)(n-2) = 2Y O(n ​​​​​​​

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