Question

Nine homes are chosen at random from real estate listings in two suburban neighborhoods, and the square footage of each home is noted in the following table. Size of Homes in Two Subdivisions Subdivision Greenwood Pinewood Square Footage 2,315 2,732 2,771 2,716 2,761 2,613 2,319 2,383 2,576 2,656 2,812 2,417 2,861 2,829 2,568 2,799 2,516 3,936 Click here for the Excel Data File a Choose the appropriate hypothesis o test there is a difference between the average szes of hom es n the two neghborhoodsa h。significan ele el Assume mean of home sizes in Greenwood and μ2 is the mean of home sizes in Pinewood s the Од (b) Specify the decision rule with respect to the p-value Reject the null hypothesis if the p-value is less than 0.10. (c) Find the test statistic tcalc. (A negative value should be indicated by a minus sign. Round your answer to 3 decimal places.) calc (d) Assume unequal variances to find the p-value. (Use the quick rule to determine degrees of freedom. Round your answer to 4 decimal places.) p-value (e) Make a decision We do not reject the null hypothesis

Answer 1

Here we have data:

Greenwood	pinewood
2315	2656
2732	2812
2771	2417
2716	2861
2761	2829
2613	2568
2319	2799
2383	2516
2576	3936

Here calculated by exacel

Excel output

t-Test: Two-Sample Assuming Unequal Variances
	Variable 1	Variable 2
Mean	2576.222	2821.556
Variance	36121.694	199115.778
Observations	9	9
Hypothesized Mean Difference	0
df	11
t Stat	-1.5175
P(T<=t) one-tail	0.0787
t Critical one-tail	1.3634
P(T<=t) two-tail	0.1573
t Critical two-tail	1.7959

a) Hypothesis:

Correct option "A"

H_o; μ₁ = μ₂

H_a; μ₁≠ μ₂

b) Reject the null hypothesis if the p-value is less than 0.10

c) t_{calc = - 1.518}

_{d) p-value = 2p ( t > | - 2.52 | ) = 0.1567}

_{e) Do not reject the} null hypothesis