Question
Please explain
Chapter 02, Problem 44 A dynamite blast at a quarry launches a rock straight upward, and 1.9 s later it is rising at a rate of 15 m/s. Assuming air resistance has no effect on the rock, calculate its speed (a) at launch and (b) 4.2 s after launch. (a)Number Units tb)Number
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Concept: we use equations of kinematics for motion in one dimension under gravity for solution as shown below, Vi = 33 621 mis-speed at launch auuM sg So (33-62 mls4-29) velociy at t42s after launch is negahve hi means Tocke is traveling doonward at***************************************************************************************************
This concludes the answers. If there is any mistake, let me know immediately and I will fix it....

Add a comment
Know the answer?
Add Answer to:
Please explain Chapter 02, Problem 44 A dynamite blast at a quarry launches a rock straight...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT