Question

8. Determine the load that can be lifted by the hydraulic system shown below. All the required information is given. Load m12

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Answer #1

This can be solved using Pascal's Law, which says that the pressure in a fluid is distributed everywhere equally.

P1 = P2

F1/A1 = F2/A2

(m1g)/(71*R12) = (m2g)/(71*R22)

(120g)/(71*62) = (m2g)/(71*122)

m2 = 120 * 144 / 36

m2 = 480 Kg

Therefore, the load that can be lifted using the hydraulic system is 480 Kg

I hope i was able to answer your question. If you need anymore explanation, please ask in comments. I would be happy to help.

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