This can be solved using Pascal's Law, which says that the pressure in a fluid is distributed everywhere equally.
P1 = P2
F1/A1 = F2/A2
(m1g)/(*R12) = (m2g)/(*R22)
(120g)/(*62) = (m2g)/(*122)
m2 = 120 * 144 / 36
m2 = 480 Kg
Therefore, the load that can be lifted using the hydraulic system is 480 Kg
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