Question 1
Confidence interval for Population Proportion is given as below:
Confidence Interval = P ± Z* sqrt(P*(1 – P)/n)
Where, P is the sample proportion, Z is critical value, and n is sample size.
We are given
x = 21
n = 100
P = x/n = 21/100 = 0.21
Confidence level = 95%
Critical Z value = 1.96
(by using z-table)
Confidence Interval = P ± Z* sqrt(P*(1 – P)/n)
Confidence Interval = 0.21± 1.96* sqrt(0.21*(1 – 0.21)/100)
Confidence Interval = 0.21 ± 1.96* 0.0407
Confidence Interval = 0.21± 0.0798
Lower limit = 0.21 - 0.0798 = 0.130
Upper limit = 0.21 + 0.0798 = 0.290
Answer: 13.0% to 29.0%
Question 2
Confidence interval for Population Proportion is given as below:
Confidence Interval = P ± Z* sqrt(P*(1 – P)/n)
Where, P is the sample proportion, Z is critical value, and n is sample size.
We are given
x = 16
n = 100
P = x/n = 16/100 = 0.16
Confidence level = 95%
Critical Z value = 1.96
(by using z-table)
Confidence Interval = P ± Z* sqrt(P*(1 – P)/n)
Confidence Interval = 0.16 ± 1.96* sqrt(0.16*(1 – 0.16)/100)
Confidence Interval = 0.16 ± 1.96* 0.0367
Confidence Interval = 0.16 ± 0.0719
Lower limit = 0.16 - 0.0719 = 0.088
Upper limit = 0.16 + 0.0719 = 0.232
Answer: 8.8% to 23.2%
Question 3
Answer: Yes
Because 95% confidence interval for Hilary exceeds the 95% confidence interval for Donald Trump.
Question 4
Based on previous discussion, Hilary Clinton will win.
So, we have estimate for p = 0.21, q = 1 – 0.21 = 0.79
Margin of error = E = 2% = 0.02
Confidence level = 95%
Critical Z value = 1.96
(by using z-table)
Sample size formula is given as below:
n = p*q*(Z/E)^2
n = 0.21*0.79*(1.96/0.02)^2
n = 1593.304
Required sample size = n = 1594
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