Hello, For question three I do not know how to start the problem. But for question...

Question

Question

Hello,

For question three I do not know how to start the problem. But for question 4 I wanted to make sure that the answer was correct.

Thank you!

Answer 1

Answer #1

your both answers are correct.

for 1st question

electric force = mass* acceleration

but electric force = q*E

so, q*E=m*a

q/m = a/E = 1.75*E13/100 =1.75*E12 (ans)

and question 2 is also correct

Answer 2

Similar Homework Help Questions

The charge for Q3 is not given. I could not find formula in book. So do...

The charge for Q3 is not given. I could not find formula in book. So do I take EA total 4.5 X 10^6 N/C. And use it for E? Then set formula like so 4.5 X 10^6= (9.0x10^9)Q/(.30m)^2 and solve for Q to get charge? I need help. ple 16-9, but calculate the electric field (magnitude and direction) at Q1 due to the Rework Exam other two charges. EXAMPLE 16-9 E above two point charges. Calculate the total ele field...
Hi! I was very confused on these two problems. Can someone please show how to do...

Hi! I was very confused on these two problems. Can someone please show how to do them and what formulas to use! Thank you! PHYS 231-01 Spring 201 Chapter 21 homework 3 Consider two infinite parallel wires. One with linear charge density +22 and the other with - as shown below. (a) What is the electric field vector&at point A? (b) What is the electric field vector E, at point B7 Set up (2 points): +2λ Calculation (2 points): Answer...
Hi, I am confused on how to find the angles to use to find the net...

Hi, I am confused on how to find the angles to use to find the net electric field vector. I hope it would be possible to work out this whole problem. Thank you! PHYS 231-01 Chapter 20 homewd 2. Consider two charged particles q1 distance from object 2 to point A is 0.5 m. What is the net electric field vector at point A? +1 μC and q2 -2 μο. The distance from object 1 to point A is 0.3...

in Part c) I am not sure how they came up with 0.5 for r for...

in Part c) I am not sure how they came up with 0.5 for r for E1. will you please give a clear details as you solve it, and please just go ahead and solve 47 so I can check my answers. Thank you. Step 6 of 8 A Electric field due to first charge is E,卡 kq Substitute 9x10, N-m2 /C2 for k, 6.00x10" С for q and 0.5 m for 5 , (9x10, N-㎡/C")(6.00x10° c) (0.5 m) E,...
for the top question, I know I use the equation E=KQ/d^2 but how do I know...

for the top question, I know I use the equation E=KQ/d^2 but how do I know it will be positive or negative? also please explain the bottom one In the figure below, Q1 (-6 HC) and Q2 (+2 uC) as shown. Use: k-9 x 109 Nm2/c2 Q1 / 1 point Q2 The electric field E2 due to Q2 at x 3 cm is: 6 x 107 N/C x6x 107 N/C 18 x 107 N/C 18 x 107 N/ zero Question...
A long non conducting cylinder has a charge density p=ar where a = 4.96 C/m^4 and...

A long non conducting cylinder has a charge density p=ar where a = 4.96 C/m^4 and r is in meters. Concentric around it is a hollow This is part of the previous page. I need help with 26, 28, 29. 12 cm 11.7 em 16.7 cm Find the total electrie flux through a spbere centered at the point charge and having radius vacuum is 88S42 × 10-12C/N·m" What is the electric field at 2 cm from theRSa The value of...

Problem 15.28 (Multistep) A strip of invisible tape 0.15 m long by 0.017 m wide is...

Problem 15.28 (Multistep) A strip of invisible tape 0.15 m long by 0.017 m wide is charged uniformly with a total net charge of 5 nC (nano 1 x10- and is suspended horizontally, so it lies along the axis, with its center at the origin, as shown in the figure below. Calculate the approximate electric field at location <0, 0.07, 0> m (location A) due to the strip of tape. Do this by dividing the strip into three equal sections,...
PLEASE ANSWER ALL QUESTIONS. ROUND ANSWER TO THE FOURTH DECIMAL PLACE WHEN NEEDED Question 5 (1.5...

PLEASE ANSWER ALL QUESTIONS. ROUND ANSWER TO THE FOURTH DECIMAL PLACE WHEN NEEDED Question 5 (1.5 points) Two point charges, q,= +1 nC and q = -4 nC, are located on the x-axis at x= 0 and x=5.00 m. What is the electric field at point x=3 m? Your Answer: Answer Question 6 (1.5 points) Two point charges, q,= +2 nC and q = -14 nC, are located on the x-axis at x= 0 and x=7 m. What is the...
I want to know how to do the questions in the simplest way possible. 25) The...

I want to know how to do the questions in the simplest way possible. 25) The magnetic field at a point P, a certain distance from a long wire carrying a current of 2 .0 A, is 1.2 x 10 T. How far is P from the center of the wire? A) 11 cm B) 22 cm C) 33 cm D) 44 cm E) 55 cm Answer: C 26) The magnetic field due to the current in a long. straight...

Hi Everyone, I just wanted to make sure that I did these two problems correctly. Thank...

Hi Everyone, I just wanted to make sure that I did these two problems correctly. Thank you! Spring 2019 Chapter 21 homework PHYS 231-01 Paige Robinsor Name: Show your work and use proper units. A surface with area vector A = 0.3-0.2 j m2 is inside an electric field E-500-400j N/C What is the electric flux passing through this surface? 1. E- 500-400 Set up (2 points): Calculation (2 points) (500 40(o.2) Answer (1 point); 230 Nmlc 2. Draw the...