Question

NMR Spectroscopy Report Data Sheet Name Date: TA' Name Signature: Lab Nection In the space below, write the answers to the NMR problems provided in the handout Include an explanation 1. CH20 86.92 doublet, 2H 01.25 triplet, 3H 6.82 doublet, 2H 2.60 quartet, 2H 2.50 singlet, 3H 2. C,H,0 3.65 broad singlet, IH 8 7.38-7.47 multiplet, 5H 84.61 singlet, 2H IR shows a broad peak at 3200-3550 cm PPM

Answer 1

the l ett-elt a 6 60 924, quartet (4) Double bond equivalent COBE) Gol4120 = 1041-12 = 5 Conelespon = one bearzene ring + one clocible bonelo Q Hote a 1.25 3 Hi troplet R e tt-elt a h 2.60 , 2 A quart He C 1 ex 6082, ZH doublet a 6.92, 2H, doublet 5 different kinds e 250, 3, singlet of proton © DBE OR CHHO = H 2 =4 ( Benzene ring pa present) H O CH-Olta a 365, broad singles, la THb b bobl, singlet 124 I 3200-3556emt Vomba Ntreele,

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