here,
the instantaneous displacement , x(t) = 34 m + ( 12.6 m/s) t - 0.036 t^2
differentiating the equation for v(t)
v(t) = 12.6 - 0.108 * t^2
at t = 5 s
v(5) = 12.6 - 0.108 * 5^2 m/s
v(5) = 9.9 m/s
2019 Spring Phys 2110-001-Sokolov Ch 02 HWw xercise 2.8 Part A A bird is flying due...
Exercise 2.8: Constants A bird is flying due east lts distance from a tall building is given by z(t) -30.0m + (12.0m/s)t (0.0390m/s) Part A What is the instantaneous velocity of the bird when t -8.00 s? Express your answer with the appropriate units. v Value
Constants PartA A bird is flying due east. Its distance from a tall building iS given by zlt) 27.0m+(11.1m/s)t-(0.0370m/s)e What is the instantaneous velocity of the bird when t 5.00 s7 Express your answer with the appropriate units. Value Units Submit Request Answer <Return to Assignment Provide Feedback
the answer needs to be Vx= (value)(Units) A bird is flying due east. Its distance from a tall building is given by a(t) 28.0m +(12.7m/s)t -(0.0370m/s)s What is the instantaneous velocity of the bird when t-5.00 s?
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A bird is flying due east. Its distance from a tall building is given by x(t)=25.0m+(12.3m/s)t−(0.0370m/s3)t3. What is the instantaneous velocity of the bird when t = 8.00 s ?
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