(a) Since 5000 is a 4 digit number so we draw 4 digit number from row 28, column 11 and proceed horizontally and ignore 0000 and the number beyond 5000. The random numbers are:
7559 (rejected), 3413, 7349 (rejected), 5021 (rejected), 7972 (rejected), 8257 (rejected), 8163 (rejected), 6412 (rejected), 4783, 7622(rejected), 9965(rejected), 9310(rejected), 6583(rejected), 6136(rejected), 9889(rejected), 5886(rejected), 9295(rejected), 7157(rejected),1755, 5564(rejected), 6541(rejected), 1425, 4770,4570,3426,7293(rejected),7837(rejected)9291(rejected),6161(rejected),1075,8010(rejected),3078,3159.\\
10 selected invoice numbers are: 3413, 4783,1755, 1425,4770,4570,3426,1075,3078,3159.
(b)
Since 5000/10=500 is an integer, so we select a random number between 001 to 500. We ignore 000 and the random number above 500 and start from row 30 and column 16 row wise. The random numbers are:
425 (accepted).\\
So the first selected unit is invoice numbered 425.
2nd selected unit is invoice numbered (425+500)=925
3nd selected unit is invoice numbered (425+2*500)=1425
4th selected unit is invoice numbered (425+3*500)=1925
5th selected unit is invoice numbered (425+4*500)=2425
6th selected unit is invoice numbered (425+5*500)=2925
7th selected unit is invoice numbered (425+6*500)=3425
8th selected unit is invoice numbered (425+7*500)=3925
9th selected unit is invoice numbered (425+8*500)=4425
10th selected unit is invoice numbered (425+9*500)=4925
c. No. Since simple random sampling is purely probabilistic sampling however systematic sampling is a mixed sampling.
Prenumbered sales invoices are kept in a sales jounal. The invoices are numbered from 0001 to...
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