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13. (12 pts) Using the following bond dissociation energies, estimate the enthalpy of the reaction for the reaction between a
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Answer #1

On reactant side we have:

1 C≡C bond

2 C-H bond

2 H-I bond

On product side we have:

4 C-H bond

1 C-C bond

2 C-I bond

Use:

Delta H = BE(reactant) - BE(product)

=1*BE(C≡C) + 2*BE(C-H) + 2*BE(H-I) - 4*BE(C-H) - 1*BE(C-C) - 2*BE(C-I)

=1*839 + 2*413 + 2*299 - 4*413 - 1*348 - 2*240

= -217 KJ

Answer: -217 KJ

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