Question

Alex, a mountaineer, must leap across a 3.3 m wide crevasse. The other side of the crevasse is 2.5 m below the point from which he leaps, as shown in the figure. Alex leaps horizontally and successfully makes the jump.

A) How much time will pass between Alex's takeoff and his landing on the other side?

B) What should be Alex's minimal horizontal speed to make this leap?

PLEASE PLEASE SHOW ALL WORK AND EXPLAIN WHY YOU USE CERTAIN EQUATIONS

Answer 1

a) given H = 2.5 m

range of this projectile = R = 3.3 m

time of projectile = t = $\sqrt{2H/g}}$

t = $\sqrt{2*2.5/g}}$

t = 0.71 sec

b) let the horizontal speed = Ux

R = Ux x t

3.3 = Ux x 0.71

Ux = 4.65 m/s

answer