Question

From my NMR result, how do I read the splits for each peak?

NaBr Br HO H2SO4 1-bromo-3-phenylpropane 3-phenyl-1-propanol r7.304 7.283 7.270 7.266 7.226 7.212 7.197 7.178 4.088 3.679 3.662 3.646 3.414 3.396 3.380 000 3.364 2.787 2.768 2.750 2.722 2.703 2.684 2.194 2.177 2.160 2.158 2.142 2.124 2.028 2.027 0.04 0.16 1.96 1.887 r1.521 1.487 r1.470 r1.468 1.451 1.433 1.428 0.929 1.91 0.10/ 1.94 60'0 0.07 0.35 0.926 0.40 0.923 A ) .912 606 0 L0.907 0.30 Hz wdd

Answer 1

See this NMR shows that this compound is not pure and so many impurity peaks are there.

In the aromatic region, 5 protons are there (7.2-7.3 ppm)

Alkyl chain protons are integrated as 1.96, 1.91 and 1.94. You can see that there are total six such protons. (3 types, 2H each). 3.5 ppm- 2H near to Br, 2.8ppm- 2H adjacent to benzene ring, 2.2 ppm-2H in between of previous mentiones 2H s. Rest are impurities.