Question

he aa ee a rkmowing question 2: The COO at the San Dvego airport has been aleted to the fact that the iro cy ng mwwer serge volume of complaints about the long wait time at the huggnge carone n d decides to collect some data Over the course of a week, he observes 5a fights for eas from the light's landing to the arrival of the fight's lggage at the carousel He oberves the rage w tm to be 3 a) Calculate a 95 % confidence interval for the estimate of the true wan time s to evaluate the suaton, be fight, he measres the t minutes, with a standard deviation of 12 minutes. (8 tstot b) How many flights would the COO have to observe in order to achieve a margin of error of only 2 minutes, at a 99% confidence level? (6 pts) ) Let's say the COO observed all 50 flights the week before Christmas. In a few sentences, please describe why might this sample be not representative of the actual average wait time. (6 pts) (sid 9) aun em adesane jenpe aua jo angeuasaudau 2ou aq adwes s A ais sund aseaid 'saouauas maj e usewas oanq yaam aua syy oS e pauasqo 000 a4 Aes s,an (sad 9) jan aouapyuoo % 66 (q e e 'saanujuz Auo jo Jou o ure e anape o apuo uj auasqo 01 aney 000 aa pinom syaiu Auew moH (sad 9) au em anu a jo teit ate J iuapyuoo %56e agejnoje (e EE aq o1 a3 3jem asejane aya sauasqo aH jasnoues au 1e a8e83n s,248 aua jo jeAue aua on 8uipuej saua a me ane to snseau ay 4y ypea Joy su os sauasqo ay pam e jo asunoo aun Ja aoS pa sappap ay 'uogenus aua aenjena 01 o ulnoues aße83ni a e aun ueM Suo au anoqe saujejduo0 o aunjon a8u e SuAjaau uaaq seuodae aya eup p p e uaa sey ode o8a1g ues aa e o0 a osn

Answer 1

Gven N 50 X 33 minute 12 minute For 95% Confidence n lera va From Stagdayd Nomal distmbuhon table FOr g5% Confidence interval (d=o-05) Zg 1.96 Emr E N 96x /2 S50 3-326 minule 3.326 minute 11E = 33 + 3-326ご36.326 min Mt= 36 .326 min IL=X-E = 29.673 m HL= 29.6 3 min Hence, at 95 Conficlence interveul Average Walt tiroe u es between (23.673-人<36-3 326) 3in For ヌニろろ 0 2 at 997 con fidence interval E 2 min From Table ,Z scove at 997. Confidence nterval is z= 2.5 N=239. 6 2.58 x 12 1 E ZO N In order to achieve emr I N 24-0 less thein Two minute No o flight observed should be 240 Sample observe, week Befure christmas actual observed waut imie, It is because, ne of Fleght mar not give e may be inreased (dung Busy Tra ffic in feshval) which can not e refteat the sample of ftight during (4eneral oe eastan) Nor festival tune

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