using 2nd equation of motion along vertical
h = ut - 0.5 gt^2
0 = 11.5* 8.08 - 0.5* g *8.08^2
g = 2.847 m/s^2
now,
C = 2 pi R
2*10^8 = 2* 3.14* R
R = 3.185*10^7 m
Acceleration due to gravity can be determined by
G M / R^2 = 2.847
6.67*10^-11* M / (3.185*10^7) ^2 = 2.847
M = 4.329*10^25 kg
==========
b)
orbital velocity,
v = sqrt ( GM / ( R + h))
v = sqrt ( 6.697*10^-11* 4.329*10^25 / ( 3.185*10^7 + 30600000) )
v = 6800 m/s
Time taken by aimless wanderer
t = 2 pi ( R + h) /v
t = 2*3.14* ( 3.185*10^7 + 30600000) / 6800
t = 57675.88 seconds
t = 16.02 hours
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Comment in case any doubt, will reply for sure. Goodluck
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