1)
Mean=330
Standard deviation= 80
Number of samples(n)= 40
a) Standard error:
b) P(Sample mean >320)
Using normal distribution table: P(Z>-0.790569)= 0.7854
So, P(Sample mean > 320)= 07854
c) P(Sample mean > 350)
Using normal distribution table: P(Z>1.58114)= 0.0569
So, P(Sample mean > 350)= 0.0569
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