Two red blood cells each have a mass of 3.75×10−14 kg3.75×10−14 kg and carry a negative...
Two red blood cells each have a mass of 3.75×10−14 kg3.75×10−14 kg and carry a negative charge spread uniformly over their surfaces. The repulsion arising from the excess charge prevents the cells from clumping together. Once cell carries −2.00 pC−2.00 pC of charge and the other −3.10 pC−3.10 pC, and each cell can be modeled as a sphere 8.20 μm8.20 μm in diameter.
What minimum relative speed ?v would the red blood cells need when very far away from each other to get close enough to just touch? Ignore viscous drag from the surrounding liquid.
What is the magnitude of the maximum acceleration ?maxamax of each cell?
Homework Answers
Part 1: Minimum relative speed is given by using conservation of energy, Einitial = Efinal , i.e. K.E. = P.E.
Part 2: Maximum acceleration is given by Newton's second law of
motion, 
F = ma
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