Question

What is the magnitude and direction (in degrees from counter clockwise from the x axis

Answers OSUniPhys1 2.3 P047 For vectors B--31- 9j and A- -41 -4j, calculate the following (o) A. B (express vour answer in vector form.,) Enter the magnitude and direction (in degrees counterclockwise from the +x-axis) for A+ B magnitude direction e counterclockwise from the +X-axis (b) A- B (Express your answer in vector form.) Enter the magnitude and direction (in degrees counterclockwise from the +X-axis) for A-B magnitude direction counterclockwise from the +x-axis Additional Materials eBook

Answer 1

This problem is based on vector addition

B = -3i - 9j A^vector = -4i - 4j a)A^vector + B^vector = -4i - 4j + -3i - 9j = -7i - 13j Magnitude = squareroot (7)^2 + (-13)^2 = 14.764 direction = It is 3rd quadrant so theta = pi + tan^-1 (y/x) 180 degrees + Tan^-1 (+ 3/7) theta implies 241.699 degrees b)A^vector - B^vector implies (-4i - 4j) - (-3i - 9j) -4i - 4j + 3i + 9j -I + 5j Magnitude = squareroot (-1)^2 + (5)^2 = 5.099 It lies in 2nd quadrant direction = Tan^-1 (5/-1) = 180 degrees - 78.69 = 101.3099