Let total mol of solution be 1 mol.
Then mol of Cu(NO3)2 is 0.127 mol
Mol of H2O = 1 - 0.127 = 0.873 mol
Molar mass of H2O,
MM = 2*MM(H) + 1*MM(O)
= 2*1.008 + 1*16.0
= 18.016 g/mol
use:
mass of H2O,
m = number of mol * molar mass
= 0.873 mol * 18.02 g/mol
= 15.73 g
= 0.01573 Kg
Now use:
Molality = mol of Cu(NO3)2 / mass of solvent in Kg
= 0.127 mol / 0.01573 Kg
= 8.07 molal
Answer: 8.07 m
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