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Problem 4: - You are a trader who trades both puts and calls on SleazeCo. Information about current market conditions is disp

Problem 4: 

You are a trader who trades both puts and calls on SleazeCo. Information about current market conditions is displayed below.

$$ \begin{array}{lclcc} \text { Stock Price } & \text { Exercise Price } & \text { Expiration Date } & \text { Call Price } & \text { Put Price } \\ \hline 88 & 90 & 1 / 12^{\text {th }} \text { of a year } & 2.8546 & 4.6032 \\ 88 & 95 & 1 / 12^{\text {th }} \text { of a year } & 1.2978 & 7.8240 \end{array} $$

The annualized continuously-compounded risk-free rate is .06 (6%). 

  1. Given the information above, are there any arbitrage opportunities?

  2. 2. If no, explain why. If yes, describe one set of trades you could make now to exploit the arbitrage opportunity. Show that this strategy generates an arbitrage profit.

  3. 3. The volatility of the return on SleazeCo. stock is 35 percent per year (i.e., σ= .35). What are the Black-Scholes values for the calls and puts above?


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Answer #1

stock price (SP) - 88 Exercise price (x) = 90 period – th of year ie, month Call premiom - 2.8546 put premium - 4.6032 calculAction for Arbitrage (1) Buy & call option (Holder) (ii) sell pat option (iii) short sell thare today. Steps for arbitrage &stoepe price(sp)= BE Exercise police (x) > 9095 period - 1 month Call premium = 1.2978 pul premium - 7.8240 calculation of faP-4 put-call y using Case (1) 8/1080 Sased on geen information in the problem, encoblem, We can calculate the arbitrage existBLACH sellores MODEL for stock options - Stock options are option contract with share of a co. as undertising and --> Value oRf = 0.06 r = 0.35 x =90 , , 2=0.1225 d. CG) +0.06+ 0.1225 )x% d = 0.35 Se In (0.9778) + 0.0101 0.1010 - 0002248+0.0101 0.101P-7) call valere - SP Y N (d) - pr of shich & N (dz) = 88 x 0.9562 – 89.5511 X 0.4168 40.1956–37.3269 2.8207 value of call -deler spaer , Rp30.06 . X-95, sa doar die es (at) + (0.06 0.125)/ 0.35 Shr In (0.9263) + 0.0101 0.1010 -0.07657 +0.010 = -0.0(PD call value & Spx (d) – profx 1 (d) - 88x0.2546 – 99.5262 (0.2236) = 27.4048 - 21.134 value of cal = 1.2687 put value = pr( P-10 working Note: 0.005 e = ? e = 2.71828 0.005 2.71828 = 2 is time Step o 2.11825 orr. ---- 2,11828 step & Step ③ Step 4

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