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When 6.55 g H, react by the following balanced equation, 32.8 g H, O are formed. What is the percent yield of the reaction? 2

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Answer #1

aus) 1 moles of H₂ (J) = mass . = 6.559 = 3.25 mol mass malau mass Ronë 2H₂(g) + O2(g) 2H₂O(1) applied POAC Rule & moles of H

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