Question

An unstrained horizontal spring has a length of 0.34 m and a spring constant of 260 N/m. Two small charged objects are attached to this spring, one at each end. The charges on the objects have equal magnitudes. Because of these charges, the spring stretches by 0.025 m relative to its unstrained length. Determine (a) the possible algebraic signs and (b) the magnitude of the charges.

Answer 1

F = 260 * 0.025 = 6.5 N

9*10^9 * q^2/(0.34 + 0.025)^2 = 6.5

so q = 7.36 * 10^-6 C

q1 = 7.36 * 10^-6 C and q2 = 7.36 * 10^-6 C

or

q1 = -7.36 * 10^-6 C and q2 = -7.36* 10^-6 C

I hope help you !!