Find the area of the indicated region under the standard normal curve. Click here to view...
Find the indicated area under the standard normal curve. To the left of z = -1.48 and to the right of z=1.48 Click here to view page 1 of the standard normal table Click here to view.page 2 of the standard normal table. The total area to the left of 2 = -1.48 and to the right of z=1.48 under the standard normal curve is (Round to four decimal places as needed.) 22 of 32 (24 complete) This Test: 57...
Find the area of the shaded region. The graph depicts the standard normal distribution with mean 0 and standard deviation 1 Click to view.page 1 of the table. Click to view.page 2 of the table The area of the shaded region is (Round to four decimal places as needed) Standard Normal Distribution Area 0 Z N .01 3.4 - 3.3 -3.2 3.1 3.0 2.9 2.8 - 2.7 .09 .0002 .0003 .0005 .0007 .0010 .0014 .0019 .0026 .08 ,0003 .0004 .0005...
formation Find the indicated area under the standard normal curve To the right of z=0.61 Click here to view.page 1 of the standard normal table Click here to view page 2 of the standard normal table. The area to the right of z=0.61 under the standard normal curve is 2709 (Round to four decimal places as needed) culator Shadent/Playetlesta pitestid=2153544778.centerwines Summer 2020 jevon rutledge & 07/29/20 7:53 PM st 3: Chapters 5, 6, & 7 Time Remaining: 00:14:07 Submit Test...
Find the area of the shaded region. The graph depicts the standard normal distribution with mean 0 and standard deviation 1 Click to view.page 1 of the table. Click to view.rage 2 of the table. 2036 The area of the shaded region is (Round to four decimal places as needed.) edge - Google Chrome -nt/Player Test.aspx?testid=215354477¢erwin-yes mer 2020 jevon rutledge & 3: Chapters 5, 6, & 7 Time Remaining 21 of 32 (7 complete) Th 0 Standard Normal Distribution Table...
ormation Find the indicated probability using the standard normal distribution. P(-1.66<z<0) Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table. P(-1.66<z<0)=(Round to four decimal places as needed.) culator Sheet tent/Player lest.aspx?testid=215354477¢erwin=yes nmer 2020 jevon rutledge 3: Chapters 5, 6, & 7 Time Remaining pt 13 of 32(7 complete) Thi Area under the standard normal distribution to the left of Z (page 1) 2 -3.4 -3.3 -3.2 -3.1...
A standardized exam's scores are normally distributed In a recent year, the mean test score was 1495 and the standard deviation was 315. The test scores of four students selected at random are 1900, 1240, 2230, and 1400 Find the z-scores that correspond to each value and determine whether any of the values are unusual The z-score for 1900 is (Round to two decimal places as needed) The Z-score for 1240 is (Round to two decimal places as needed.) The...
The test statistic of z= - 1.86 is obtained when testing the claim that p < 0.22. a. Using a significance level of a=0.10, find the critical value(s). b. Should we reject Ho or should we fail to reject Ho? Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. a. The critical value(s) is/are z= 1. (Round to two decimal places as needed. Use a...
Find a Z-score such that 2% of the total area is to the left of z. (Hint: Use the table backwards.) Click here to view page 1 of the table. Click here to view page 2 of the table. Choose the closest z-score such that 2% of the total area is to the left of z. Z= (Round to two decimal places as needed.) X- Area Under a Normal Curve to the Left of z, where z= 0 z 0.00...
Find a Z-score such that 3% of the total area is to the right of z. (Hint: Use the table backwards.) Click here to view page 1 of the table. Click here to view page 2 of the table. Choose the closest z-score such that 3% of the total area is to the right of z. ZE (Round to two decimal places as needed.) X- Area Under a Normal Curve to the Left of z, where z= 0 z 0.00...
So, converted to a z interval, we wish to find P(0.26 < z < 0.79). Recall that since the z value is between two different values, we will need to subtract the table areas for Z, = 0.26 from the table area for z, = 0.79. Use this table to determine P(Z < 0.26) and P(Z < 0.79). Substitute these values into the formula to find the probability. (Round your answer to three decimal places.) P(0.26 < z < 0.79)...