A charge of 9.00 mC is placed at each corner of a square 0.270 m on a side.
Determine the magnitude of the force on each charge.
given charge q = 9 m C = 0.009 C
r = 0.27 m
F1 = F4 = k q1 q2 / r2
= 9 X 109 X 0.0092 / 0.272
= 107 N
the distance is a = ( 0.272 + 0.272 )1/2
a = 0.381 m
F3 = k q3 q2 / a2
= 9 X 109 X 0.0092 / 0.3812
= 5.022 X 106 N
the angle is = 450
X - component is
Fx = F1 + F3 sin
= 107 + 5.022 X 106 X sin45
= 1.355 X 107 N
Fy = F4 + F3 sin
= 107 + 5.022 X 106 X sin45
= 1.355 X 107 N
F = ( Fx2 + Fy2 )1/2
F = ( (1.355 X 107 )2 + (1.355 X 107 )2 )1/2
F = 19127271.11 N
the magnitude of the force on each charge is F = 19127271.11 N
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