In the arrangement of the figure, billiard ball 1 moving at a speed of 1.8 m/s...
In the arrangement of the figure, billiard ball 1 moving at a speed of 1.6 m/s undergoes a glancing collision with identical billiard ball 2 that is at rest. After the collision, ball 2 moves at speed 0.8 m/s, at an angle of θ2 = 55°. mal li if (a) What is the magnitude of the velocity of ball 1 after the collision? m/s (b) What is its direction? o clockwise from the +x axis (c) Do the given data...
A billiard ball moving at a speed of 7.95 m/s strikes an identical stationary ball a glancing blow. After the collision, one ball is found to be moving at a speed of 1.80 m/s in a direction making a 59.5 ° with the original line of motion. What is the speed of the other ball? At what angle is it moving? Give your answer in degrees. (Hint: use conservation of linear momentum)
If you don't answer all of it then youll receive bad rate and ill check if answer is right or not In Figure (1), a 3.50 q bullet is fired horizontally at two blocks at rest on a frictionless table. The bullet passes through block 1 (mass 1.13 kg) and embeds itself in block 2 (mass 1.65 kg). The blocks end up with speeds v1 = 0.550 m/s and v2 = 1.45 m/s (see Figure (2)). Neglecting the material removed...
One billiard ball is shot east at 1.7 m/s . A second, identical billiard ball is shot west at 0.90 m/s . The balls have a glancing collision, not a head-on collision, deflecting the second ball by 90∘ and sending it north at 1.33 m/s . 1) What is the speed of the first ball after the collision? Express your answer to two significant figures and include the appropriate units. 2) What is the direction of the first ball after...
A billiard ball is shot east at 2.80 m/s. A second, identical billiard ball is shot west at 1.20 m/s. The balls has a glancing collision, not a head-on-collision, deflecting the second ball by 90° and sending it north at 1.60 m/s. What is the angle that the velocity of the first ball makes after the collision, with respect to the east direction?
A stationary billiard ball with a mass of 0.17kg, is sturck by an identical ball moving at 4.0 m/s. After the collision, the second ball moves 60 degrees to the left of its original direction. The stationary ball movies 30 degrees to the right of the moving ball's original direction. What is the velocity of each ball after the collision? A stationary billiard ball, with a mass of 0.17 kg, is struck by an identical ball moving at 4.0 m/s....
Billiard ball A of mass mA = 0.125 kg moving with speed vA = 2.80 m/s strikes ball B, initially at rest, of mass mB = 0.140 kg . As a result of the collision, ball A is deflected off at an angle of θ′A = 30.0∘ with a speed v′A = 2.10 m/s, and ball B moves with a speed v′B at an angle of θ′B to original direction of motion of ball A. Part C Solve these equations...
Billiard ball A of mass mA = 0.119 kg moving with speed vA = 2.80 m/s strikes ball B, initially at rest, of mass mB = 0.141 kg . As a result of the collision, ball A is deflected off at an angle of θ′A = 30.0∘ with a speed v′A = 2.10 m/s, and ball B moves with a speed v′B at an angle of θ′B to original direction of motion of ball A. Solve these equations for the...
A billiard ball moving at 6.00 m/s strikes a stationary ball of the same mass. After the collision, the first ball moves at 4.94 m/s at an angle of 34.5° with respect to the original line of motion. Assuming an elastic collision (and ignoring friction and rotational motion), find the struck ball's velocity after the collision. What is the magnitude of the velocity and the direction o counter-clockwise from the original direction of motion?
We observe a glancing collision between two billiard balls of the same mass. The first ball is incident at a speed of 5.72 m/s, strikes the second ball (initially at rest) and moves off with a speed of 5.03 m/s at an angle of 28.5° counterclockwise from the original line of motion. The second ball is initially at rest and after the collision moves off with a velocity which we wish to describe with respect to the first ball's original...