You are asked to prepare 100 mL of a propanate/propanoic acid buffer with a pH of 5.5.
Ka of C2H5COOH=1.34*10^-5
If you used 40 mL of a .1 M C2H5COOH solution, what volume of a .4 M Na C2H5OO solution would you need to prepare the solution?
ANSWER:-
using formula
M1(C2H5COOH)V1 (C2H5COOH) = M2 (C2H5OO ) V2 (C2H5OO )
0.1 X 40 mL = 0.4 x V2
V2 = 10 mL Of (C2H5OO ) needed to prepare 0.4 M Na C2H5OO solution.
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