Question

Auto insurance premiums. Suppose a newspaper article states that the distribution of auto insurance premiums for...

Auto insurance premiums. Suppose a newspaper article states that the distribution of auto insurance premiums for residents of California is approximately normal with a mean of 1619. The article also states that 25% of California residents pay more than 1940.

1. What is the Z score that corresponds to the top 25% (or the 75thth percentile) of the standard normal distribution? Round your answer to 4 decimal places.

2. What is the mean insurance cost?

3. What is the cutoff for the 75thth percentile?

4. Identify the standard deviation of insurance premiums in LA. Round your answer to two decimal places.  Hint: Use the information from the first 3 questions in this problem and the formula for finding the z-score.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

イ+) 0.6 4S = 1910-1619 ニ475.91

Add a comment
Know the answer?
Add Answer to:
Auto insurance premiums. Suppose a newspaper article states that the distribution of auto insurance premiums for...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Auto insurance premiums. Suppose a newspaper article states that the distribution of auto insurance premiums for...

    Auto insurance premiums. Suppose a newspaper article states that the distribution of auto insurance premiums for residents of California is approximately normal with a mean of 1598. The article also states that 10% of California residents pay more than 1850. 1. What is the Z score that corresponds to the top 10% (or the 90thth percentile) of the standard normal distribution? Round your answer to 4 decimal places. 2. What is the mean insurance cost? 3. What is the cutoff...

  • MW-Practice: Provien 2 Problem Value: 1 point(s). Problem Score: 75%. Attempts Remaining: Unlimited. Suppose a newspaper...

    MW-Practice: Provien 2 Problem Value: 1 point(s). Problem Score: 75%. Attempts Remaining: Unlimited. Suppose a newspaper article states that the distribution of auto insurance premiums for residents of California is approximately normal with a mean of 1633. The article also states that 30% of California residents pay more than 1875. percentile) of the standard normal distribution? Round your 1. What is the Z score that corresponds to the top 30% (or the 70 answer to 4 decimal places. 524 2....

  • In a normal distribution, the mean corresponds to: Standard Score: z = Percentile: Which of the...

    In a normal distribution, the mean corresponds to: Standard Score: z = Percentile: Which of the following statements are TRUE about the normal distribution? Check all that apply. A data value with z-score = -1.5 is located 1.5 standard deviations below the mean. The mean corresponds to the z-score of 1. The Empirical Rule only applies when a value is exactly 1, 2, or 3 standard deviations away from the mean. A z-score is the number of standard deviations a...

  • Suppose that the distribution of marks on an exam is closely described by a normal curve...

    Suppose that the distribution of marks on an exam is closely described by a normal curve with a mean of 65. The 84th percentile of this distribution is 75. (a) What is the 16th percentile? (b) What is the approximate value of the standard deviation of exam marks? (c) What z-score is associated with an exam mark of 50? (d) What percentile corresponds to an exam mark of 85? (e) Do you think there were many marks below 35? Explain.

  • Suppose that the distribution of marks on an exam is closely described by a normal curve...

    Suppose that the distribution of marks on an exam is closely described by a normal curve with a mean of 65. The 84th percentile of this distribution is 75. (a) What is the 16th percentile? (b) What is the approximate value of the standard deviation of exam marks? (c) What z-score is associated with an exam mark of 50? (d) What percentile corresponds to an exam mark of 85? (e) Do you think there were many marks below 35? Explain.

  • Information from the American Institute of Insurance indicates the mean amount of life insurance ...

    Information from the American Institute of Insurance indicates the mean amount of life insurance per household in the United States is $135,000. This distribution follows the normal distribution with a standard deviation of $42,000. If we select a random sample of 76 households, what is the standard error of the mean? (Round your answer to the nearest whole number.) What is the expected shape of the distribution of the sample mean? What is the likelihood of selecting a sample with...

  • CNNBC recently reported that the mean annual cost of auto insurance is 995 dollars. Assume the...

    CNNBC recently reported that the mean annual cost of auto insurance is 995 dollars. Assume the standard deviation is 295 dollars, and the cost is normally distributed. You take a simple random sample of 13 auto insurance policies. Round your answers to 4 decimal places. What is the distribution of XX? XX ~ N(,) What is the distribution of ¯xx¯? ¯xx¯ ~ N(,) What is the probability that one randomly selected auto insurance is less than $1019? a simple random...

  • The rent for a one-bedroom apartment in Southern California follows the normal distribution with a mean...

    The rent for a one-bedroom apartment in Southern California follows the normal distribution with a mean of $2,475 per month and a standard deviation of $290 per month. The distribution of the monthly costs does not follow the normal distribution. In fact, it is positively skewed. What is the probability of selecting a sample of 45 one-bedroom apartments and finding the mean to be at least $2,365 per month? (Round z value to 2 decimal places and final answer to...

  • Information from the American Institute of Insurance indicates the mean amount of life insurance per household...

    Information from the American Institute of Insurance indicates the mean amount of life insurance per household in the United States is $165,000. This distribution follows the normal distribution with a standard deviation of $40,000. If we select a random sample of 50 households, what is the standard error of the mean? (Round your answer to the nearest whole number.) What is the expected shape of the distribution of the sample mean? What is the likelihood of selecting a sample with...

  • Claims filed under auto insurance policies follow a normal distribution with mean 19,400 and standard deviation...

    Claims filed under auto insurance policies follow a normal distribution with mean 19,400 and standard deviation 5,000. What is the probability that the average of 25 randomly selected claims exceeds 20,000?

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT