Question

O pts) Calculate the pin reactions at A, B and Dif P = 50 N, Q = 30 N, L = 5 m, d= 4 m and h = 10 m. (A, B and D are all pin connections) P=SON { Yi=0 RAY + Roy-Q=0 FBD For Euty S. - RAY + Roy = 30N {xi=0 Ron-Rax - P=0 Rox-RAX= SON eam Son Ray my RANCA LL SMA ED tRb xh (5m) Q - (10m) Roy = 0 (5m) (30N) - (10m) Rsy=0 Į Yi = 0 . RAgQ+ RByto May - Sunt IGN=0 Ray - 1 um where did this cofom 7

Answer 1

- pran free body diagram > Curen p=50N, O=30N, 2=5 m, d = 4 m - Tom Take tor que about point A :- {TA =0 8x2 - Royr (9L) - Px (dth =0 or (30N) (50) - Royx (2 x 5m) - SON (4m + 100) = 0 or Roy = -550 Her negative sign shows that considered direction of Reaction an opposite & Fy = 0 Ray + Roy - Q = 0 or Ray = Q - Roy = 300-(-550) or [Ray = 654 & fx = 0 RAx- Roe-poo RAR- Roep

page o Rae - Rpx - SON - you for body diagrams of pod 10 J Roy KBZ Ray a Take Torque about point Bi- Royx (2L) - 4x2 – Rnxxh=0 n lasm) - (30M)(5m) - Raxx (100) =0 or [RAx=70 N hem en - RAx-SON 7ON-SON = 2 ON Roz- Rox - ON RA= RAx² + Ray = √ (GON) + (05 ND 2 TRA= 110.113N D R = Rout+ Roy? - / (200) ²+1-950) 2 Rp 56-52N