Question

For the following reaction, show the product of one mole of reagent adding across the triple bond, and then show the product of a second mole of reagent.

Answer 1

Concepts and reason

The concept used to solve this problem is determined product of addition reaction on alkyne

Fundamentals

Alkyne : This compound has at least one triple bond. The general formula of this class of compound is .

Markovnikov's Rule: When a alkyl halide HX or HOH is added to an unsymmetrical alkene, the hydrogen becomes attached to the carbon with the most hydrogen attached to it already.

Anti-Markovnikov's Rule: When a alkyl halide HX is added to an unsymmetrical alkene, in the presence of peroxide or light the hydrogen becomes attached to the carbon with the least hydrogen attached to it already.

The given alkyne is as follows:

The addition of on alkyne is occurring via a polar mechanism as follows:

The reaction between 4-methylpent-1-yne and 1 mole of is following:

Mechanism:

The addition of on 4-methylpent-1-yne occurs as follows:

The addition of 2 mole of on alkyne is occurring vai a polar mechanism as follows:

The reaction between 4-methylpent-1-yne and 2 mole of is following:

Ans:

Thus, the product of addition reaction of 2 mole of on alkynes is