Homework Answers
Solution)
(a) Force acting on proton at A, F = q * EA
= 1.6 x 10^-19 * 43
= 6.88 x 10^-18 N
(b)
Here, EA = 2( EB ) ( the lines separation on B is twice that of A )
So, EB = EA / 2
= 43 / 2
= 21.5 N/C (Ans)
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