Let,
A : Event that adults regularly consume coffee.
P( A ) = 65% = 0.65
B: Event that adults regularly consume soda.
P( B ) = 40% = 0.4
P( A and B ) = 0.35
a)
Probability that a randomly selected adults regularly drink coffee but doesn't drink soda is,
= P( A ) - P( A and B )
=0.65 - 0.35
= 0.3
b)
Probability that a randomly selected adult consumes coffee, soda or both is,
P( A or B )= P( A ) + P( B ) - P( A and B )
P( A or B )= 0.65 + 0.40 - 0.35
P( A or B ) = 0.7
c)
Probability that a randomly selected adult doesn't consumes at least one of these two product is ,
P( A or B )c = 1 - P( A or B )
P( A or B )c = 1 - 0.7
P( A or B )c = 0.3
Will rate!! suppose that 65% of all adults regularly consume coffee 40% regularly consume carbonated soda,...
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