Question

A) 0.85 B) 0.71 C 0.29 D) 0.56 8) A survey asked 863 people how many times per week they dine out at a restaurant. The results are presented in the following table. Number of Times Frequency 142 236 113 60 27 21 863 Consider the 863 people to be a population. Let X be the number of times per week a person dines out for a person sampled at random from this population. Find the probability that a person dines out 4 or more times per week A) 0.536 B) 0.130 D) 0.87 曰

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Answer #1

dines out 4 or more times per week,it means dining out 4 or 5 or 6 or 7 times.

so, P(dines out 4 or more times per week) = (60+27+21+4)/863=   0.130

option B) is answer

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