part b ? also
part d) By how much could the largest observation be decreased without affecting fs? (Enter your answer to one decimal place.) My answer for part d was : 108.4-81.5 =26.9 or -26.9 , which the homework says is wrong answer
b)
there is no outliers.
there is slight positive skew to the data
the variation seems quite large
c)
The fourth spread is measured using the lower fourth and upper fourth. So, until and unless we reduce it to a value less than upper fourth i.e. 70.35, the fourth spread won't change.
So, the maximum decrease that can be done = 108.4-70.35=38.05
part b ? also part d) By how much could the largest observation be decreased without affecting...
please help me compute ALL parts C and D Consider the following observations on shear strength (MPa) of a joint bonded in a particular manner 22.8 40.4 16.4 726 36.6 108.2 0.0 4.4 33.1 667 81.5 (a) What are the values of the fourths? (Enter your answers to two decimal places.) lower fourth 26.4 MPa MPe upper fourth 69.65 What is the value of f? 4325MPa (b) Construct a boxplot based on the five-number summary. 20 40 60 80 100...
please just complete answer (d) Consider the following observations on shear strength (MPa) of a joint bonded in a particular manner 21.0 40.4 16.4 72.26.6 110.0 30.0 4.4 33.166.7 81.5 (a) What are the values of the fourths? (Enter your answers to two decimal places.) lower fourth 25.50 upper fourth 69.45 MPa MPa What is the value of f? 43.95 MPa (b) Construct a boxplot based on the five-number summary. 40 60 80 40 60 80 100 O 20 20...