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Two point charges qi- +2.40 nC and6.50 nC are 0.100 m apart. Point A is midway between them; point B is 0.080 m from qi and 0.060 m from q2. Take the electric potential to be zero at infinity. (a) Find the electric potential at point A. (b) Find the electric potential at point B. (c) How fast would a 2.50 nC charge with a mass of 1.00 grams be moving if it started from rest at point B and moved to point A? Assume that the charge is only acted upon by the electric force from the two stationary charges 0.050 m-><-0.050 m 91

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Answer #1

Concept :- here we find potential due to individual charge and then add them algebraically to find the total potential, and then we use conservation of energy principle to find out the final speed,

Ovs члье.osm) 2 WT600.DSw) 2 0.08m 2-***************************************************************************************************
This concludes the answers. If there is any mistake, let me know immediately and I will fix it....

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> En el literal C la respuesta esta incorrecta. Lo correcto sería -8.25x10´´-8 J

Pochaco Retana Wed, Nov 3, 2021 3:21 PM

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