If I connect a large number of 75.0 microFarads capacitors in parallel across a 260.0 Volt...
Homework Answers
voltage V = 260 V
energy U = 180 J
energy stored in the capacitors
U = (1/2) CV2
180 = 0.5 * C* 2602
C = 5325μF
So we need 5325μF capacitance for 180 J ofenergy
we have each capacitor has75μF
number of capacitors C = 5325/75 = 71
so 71 capacitors are connected in parallel for 180 J of energy
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