Assume that the kinetic energy of a 1500kg car moving at 135km/h could be converted entirely into heat.
KE = 1/2mv^2
First, convert km/h to m/s.
135 km/h x (1000 m / 1 km) x (1 hour / 3600 seconds) = 37.5 m/s
Now use the KE equation
KE = (1/2)(1500 kg)(37.5 m/s)^2
KE = 1.05 * 10^6 Joules
Now use the energy in the equation q = mcdeltaT
1.05 * 10^6 J = m(4.18 J/g-C)(55 C - 22 C)
m = 7.6 * 10^3 grams
KE= 0.5mv^2. remember for this to be in joules m and v must be in metres per second and kg. so 135 km/h = 110/3.6 = 37.5 ms^-1 .
substituting into the equation,
we get KE = 1054687.5 J.
Thermal energy = MC(T2-T1) J ...where, M = mass of water in grams, C = 4.2 (specific heat capacity).
Kinetic Energy = Thermal Energy
therefore, mass M = Kinetict Energy/ (temp change x 4.2) = 1054687.5/(33 x 4.2) = 7609.58 g = 7.61 kg.
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