Question

Many free radicals combine to form molecules that do not contain any unpaired electrons. The driving force for the radical-radical combination reaction is the formation of a new electron-pair bond. Write Lewis formulas for the reactant and product species in the following chemical equation. Include nonbonding electrons. N(g)-->NO(g)-->NNO(g

Answer 1

Concepts and reason

The concept used to solve this problem is based on the Lewis structure.

Lewis structure is a structure representing the bonding between atoms of a molecule and lone pair of the electrons which are present in molecule.

Fundamentals

Lewis structure can be drawn by counting the total number of valence electrons in the molecule. The rules for drawing Lewis structure are as follow.

First write the structure of the compound by placing bonding atoms next to each other. The least electronegative atom occupies the central position.

Count the total number of valence electrons in the molecule. add the number of negative charge to the total number of valence electrons and subtract the number of positive charge from total number of valence electrons.

Complete the octets of the atoms bonded to central atom.

Part 1

The atomic number of nitrogen is 7 and valence electrons present in nitrogen is 5. Thus, Lewis structure of N atom is as follow.

Part 2

The valence electrons in N atom is 5 and in O atom is 6. Total number of valence electrons in NO is 11. These electrons are distributed in such a way that every atom has complete octet. Thus, Lewis structure of NO is as follows.

Part 3

The total number of electrons in NNO is 16. So, these electrons are distributed in such a way that every atom has complete octet. Thus, Lewis structure is written as follow.

$:N=N=0 $

Ans: Part 1

The Lewis structure of N atom is as follow.