If n=14, ¯xx¯(x-bar)=45, and s=13, construct a confidence
interval at a 90% confidence level. Assume the data came from a
normally distributed population.
Give your answers to one decimal place
If n=14, ¯xx¯(x-bar)=45, and s=13, construct a confidence interval at a 90% confidence level. Assume the...
If n=13, ¯xx¯(x-bar)=47, and s=11, construct a confidence interval at a 80% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place
If n=15, ¯xx¯(x-bar)=48, and s=15, construct a confidence interval at a 99% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place. < μμ < Submit Question
If n=16, ū=35, and s=13, construct a confidence interval at a 90% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place. *<u<
1:41 ohm.lumenlearning.com If n=11, 7(x-bar)=44, and s=10, construct a confidence interval at a 90% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place. Submit Question
If n=15. (x-bar)=50, and s=9, construct a confidence interval at a 80% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place. <μ<
1. If n=28, (x-bar)=49, and s=6, find the margin of error at a 95% confidence level. Give your answer to two decimal places. 2. In a survey, 10 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $39 and standard deviation of $8. Find the margin of error at a 90% confidence level. Give your answer to two decimal places. 3. If n=20, (x-bar)=50, and s=20, construct...
if n=27,(has a line on top of x)--> x(x-bar)=38, and s=20, construct a confidence interval at a 90% confidence level. Assume the data came from a normally distributed population. Give answer in one decmil place.
part 1. A student was asked to find a 95% confidence interval for the proportion of students who take notes using data from a random sample of size n = 79. Which of the following is a correct interpretation of the interval 0.12 < p < 0.32? There is a 95% chance that the proportion of notetakers in a sample of 79 students will be between 0.12 and 0.32. There is a 95% chance that the proportion of the population...
Construct the indicated confidence interval for the population mean μ using the t-distribution. Assume the population is normally distributed. Construct the indicated confidence interval for the population mean μ using the t-distribution. Assume the population is normally distributed c-0.98, x-12.4, s 0.91, n 13 Round to one decimal place as needed.)
Construct the indicated confidence interval for the population mean y using the t-distribution. Assume the population is normally distributed c=0.90, x= 14.6, s = 2.0, n= 10 The 90% confidence interval using a t-distribution is (Round to one decimal place as needed.)