Question

Use the References to access important values if needed for this question. Two 1-L beakers, A and B, each containing a different aqueous solution of maltose (a nonvolatile sugar with MW-342.30 g/mol) are placed together in a box, which is then sealed. The temperature remains constant at 20 °C. Initially, there is 740 mL of solution in A and 140 mL of solution in B. As the solutions stand in the sealed box, their volumes change slowly for a while. When they stop changing, beaker A contains 460 mL and beaker B contains 420 mL. It is then determined that the solution in A is 1.54 M in maltose and has a density of 1.20 g mL, (a) What is the molar concentration of maltose in the solution in beaker B at the end? (b) Calculate the concentration of maltose in the solution in A at the start. M (c) Calculate the concentration of the maltose in the solution in B at the start M (d) The vapor pressure of pure water at 20 °C is 17.5 tor What is the pressure of water vapor in the box at the end, after the volumes have stopped changing? torr Submit Answer 4 question attempts remaining

Answer 1

Bms GNem data Demsity glmL uoluma IL Molbaity Mi 1-S4M. Volume, 420mL a) Tha conontsation Solution B'a obmaltose MIN M2VZ s4 x 42Dx103= M2x460x103 M2 460 X13 M2 40M b Tha coniortoahon or maltose w Solution AvA MiViMevp Givem data, Vi z 740mL V 420m Vi DIx Qchx hS' 7YOX13 ht8 0 The contonttioh of ose im Solucon b CamScanner

Vi 14o mL M= 140M Vf = 460ML 4ox 460x10 140x10 4,6M uates Vapous remains vapou Poessuoe a not moas Concontration unchanged and volume remains Same The poousua ates Uapour 17/6t0 cs Scanned with CamScanner