Question

Homework 2 Chapter 17 Do not put any work or answers on this page. You must show your work to receive full credit for a correct answer. Answers MUST be in correct form. Unknown Variable calculated value & correct units Review Deadline 1 pm EST Thursday Jan 24 2019 Due Date 1 pm EST Tuesday Jan 29 2019 1) An electric field of magnitude 1.80 (10)6 N exerts a force of 9.00 N on a test charge placed in the field. a) When the test charged measured the force of 9.00 N it was 20 cm from the unknown charge. What was the magnitude of the unknown charge? q-? b) What is the magnitude of the test charge? q? 2) Two charges having the same charge magnitude experience an attraction force of 3.60 N when the charges are 30 cm apart. What is the charge magnitude in micro coulombs and the sign of each chge? q1q2 For problems 3 and 4 you MUST make a sketch of the layout of the charges on a horizontal line (x axis). And when determining the direction of the force for each pair you MUST use the horizontal charge arrangement as show in the 3 charge examples. If you do not do those two things-your work for problems 3 and 4 will not be reviewed and when submitted for grading there will be zero partial credit for incorrect answer and a 1 point reduction for correct answers. 3) Three charges are situated along the X axis. The first charge, q1 -4 μc, is located at-40 cm on the x axis. The second charge, q2 -5 με, is located at the-10 cm on the x axis. The third charge, q3 #-6 c, is located at +50 cm on the x axis. a) Determine the following values: F12, F13, F2,3? Using your values from part al: b) Determine the total force acting on each charge due to the other two charges: 4) Four charges are situated along the X axis The first charge, q1 = +6 μ, is located at origin on the x axis. The second charge, q2-9 uc, is located at the +30 cm The third charge, q3 +7 με, is located at +60 cm on the x axis. The fourth charge, q48 uc, is located at +90 cm on the x axis. Determine the total force on charge qa due to the others. 5) A charge of ++250uc is moved from a position where the electric potential is 50v to a position where the electric potential is 150v. What is the change in potential energy of the charge due to the change in position.

Answer 1

(a) E = 1/4 pi epsilon_0 q_1/r^2 1.80 times 10^6 = 9 times 10^9 times q_1/400 times 10^-4 q_1 = 0.2 times 10^-3 times 400 times 10^-4 = 8.0 times 10^-6 c = 8mu c (b) F = q_0 E g middot N = 1.8 times 10^6 times q_0 q_0 = 5 times 10^-6 c = 5mu c