Question

1. A 5.4 kg cat and a 2.1 kg bowl of tuna fish are at opposite ends of the 4.0-m-long seesaw. (Figure 1)

How far to the left of the pivot must a 3.7 kg cat stand to keep the seesaw balanced? Express your answer to two significant figures and include the appropriate units.

20 m 2.0 m

2. Vector A⃗ =5i^+3j^ and vector B⃗ =3i^−6j^+4k^.

Part A:What is the cross product A⃗ ×B⃗ ? Find the x-component.

Part B: Find the y-component.

Part C:Find the z-component

Answer 1

n S а») за ш 2 Tout = 0: To Fr Famg. 2-14 х2 + 3 -52x d = 5-43x 2 2-13- + 3. 2d - S-4х2 3.+d - (s-4 – 2-) а 3- 3х2 1-18 m wult 3.2 Scanned with CamScanner