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Draw the Haworth projection of beta-D-fructose by

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Concepts and reason

The concept used to solve this problem is based on the Haworth projection of an organic compound.

The Haworth projection is basically used to represent sugars in the cyclic form. It tells which atom is above the plane and which is below the plane.

Fundamentals

The Haworth structure can be drawn from the Fischer projection. The characteristics of Haworth projection is as follow.

The carbon atom is implicit type of atom in the Haworth structure. The carbon present on the 1 number is known as anomeric carbon.

Hydrogen atoms are present on carbon atom.

A thicker line represents the atoms which are closer to observer.

First write the Fischer projection of D-fructose as follow.

СН, ОН
НО
-н
НО-
— H
н—— он
0=)
HOʻНЭ

Now, assign numbers to each carbon in the structure as follow.

1 СН,ОН
2 С=0
-ОН
5—ОН
СН, ОН

Now, from the Fischer projection draw the Haworth projection as follow.

1 CH OH
2c-o
ОН
Но
—н
—ОН
5н но и
CH,OH
н—
Он
н
—ОН
СН,ОН

The atoms on left side of Fischer projection will present on upper position in the five-membered ring and the atoms on right side will present lower position in the ring.

Ans:

The Haworth projection of β\beta -D-fructose is as follow.

HOCH,
олон
Кнно,
СН, ОН
он н

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Draw the Haworth projection of beta-D-fructose by labeling the furanose ring. The anomeric carbon is shown....
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