E = Σ kQ / d²
At the point in question, the field due to q1 is positive (to the right), due to q2 is negative (to the left) and due to q3 is positive (to the right). Then
E = 8.99e9N·m²/C² * (6.50/(0.02m)² - 1.71/(0.01m)² + 2.37/(0.03m)²) * 1e-6C
E = 1.605e7 N/C ◄ field at 1 cm left of center marble
For fourth marble:
F = q*E = 3.68e-6C * 1.605e7N/C = 59.1 N ◄ [Verify the value of q as it is not clear in the image]
and the direction is "to the right." ◄
Three charged marties are glued to a nonconducting surface and are placed in the dagram as...
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