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These scores would be easier to visualize and interpret if they were graphed as a histogram. To do that, we first need to group them into class intervals and present them as a frequency distribution of grouped scores Table 2 divides the range of these 25 schools academic performance into ten intervals. Based on the information provided in Table 1, use the dropdown menus to fill in the rest of Table 2 and complete the remainder of the problem. Note that the scores are listed in lowest to highest order Table 2 Class Interval (Percentage of students passing at least one AP exam f 90-99 80-89 70-79 60-69 50-59 40-49 30-39 20-29 10-19 0-9 4 Total (N) In the frequency distribution table, for the interval of 30-39, the real lower limit is limit is , and the real upper

Now complete the following histogram. (Hint: Use a different orange rectangle for each class interval.) NUMBER OF SCH0OLS 10 20 30 40 50 60 70 80 90 100 ACADEMIC PERFORMANCE Clear ALL Flash Player WIN 32,0,0,114

math   Statistics-And-Probability   
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Answer #1

The frequency table is as below.

CI f
90-99 3
80-89 4
70-79 3
60-69 4
50-59 3
40-49 2
30-39 2
20-29 1
10-19 2
0-9 1
Total 25

There are 4 observation between 60-69, 3 observation between 50-59, 2 observation between 40-49, and 2 observation between 30-39.

For the interval 30-39, the real lower limit is 30-0.5=29.5 and the real upper limit is 39 +0.5 39 .

The histogram is as below.

NUMBER OF SCHOOLS 10 20 30 40 50 60 70 80 90 100 ACADEMIC PERFORMANCE

The respective blocks of the class intervals are marked.

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