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the dispacement of particle#1 is r1(t)=1i-5tj and the displacement of particle #2 is r2(t)=-4ti+4tj. Find V12...

the dispacement of particle#1 is r1(t)=1i-5tj and the displacement of particle #2 is r2(t)=-4ti+4tj. Find V12 the relative velocity particle 1 with respect to particle 2. you must sketch a graph to illustrate your result

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Answer #1

7, 11-S13 A011-5t1) dly dt cAT 4 3 2- S- 3 4 4 =S--41+ 43 5 3+41-41 +41-93

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the dispacement of particle#1 is r1(t)=1i-5tj and the displacement of particle #2 is r2(t)=-4ti+4tj. Find V12...
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