Question

Question Assume that a monochrome video display system has the following characteristics: 10 marks the resolution is 320 pixels (across) by 200 pixels (down) the origin (0, 0) is in the upper left corner the most significant bit (MSB) of each byte corresponds to the left-most pixel represented the first byte of the video buffer is called VIDBASE Answer the following questions: How many bytes are there per scan line? Please list the calculation procedure and the results. [2 marks] a. How many bytes are required to store the entire video buffer? (assuming that no bytes are wasted). b. Please list the calculation procedure and the results. [3 marks What formula is used to calculate the address of the byte that contains the pixel at location (x, y) on the c. [5 marks] window?

Answer 1

Every row of pixels is called as scan line. Collection of scan lines makes a video buffer.

acros the row Simce each scan lime is diylay Lime containd 320 pireels Eaeh c Scan Cmonorlrome) is of ene byte Each pinel eme 320 X 1 So, dodal m Bne Scam lne 320 byle pines(dain) lmes Since there Onero must be erealy aとえss 200 are 200 Scam byes rquired to store thovideo Size of each scan lie total bufer 200X le20 0, X 32 0 l 64,00 0 byte first byls is VID RASE det addauss VI0BASE be base addras base aldrcs t 320x Adras (n,y) 17

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