Question

Everyone's favorite flying sport disk can be approximated as the combination of a thin outer hoop and a uniform disk, both of diameter Da=0.273 m. The mass of the hoop part is mh = 0.130 kg and the mass of the disk part is me=0.040 kg. Imagine making a boomerang that has the same total moment of inertia around its center as the sport disk. The boomerang is to be constructed in the shape of an "X," which can be approximated as two thin, uniform rods joined at their midpoints. If the total mass of the boomerang is to be mp = 0.225 kg, what must be the length L, of the boomerang? L = Cross-sectional view

Answer 1

dise = ma- 0.0 40 hoop (mn 0-130 kg mas dink aud hoop is D 02 3 m mars dianere Rakius R D $Thise 0a13 m 20 f Frentia about Center igiren mh Rd t ma RD Moment 1 as Io- 2. Io0.13/0-273 0.040 A O273 22

2P 2.42x103+ 0.TH55 K10 Io-3.1 6 X1lo the Mement l Inedia boomerany is given as- 2 Ib mb Lbt Mb 12 12 L6 0.225K 12 12 0. २२5XL, 3.16x 10 2 Lb0-1689324 Lb 0.41m 1689 m Answes