The H NMR spectrum below corresponds to a hydrocarbon with the molecular formula CoH 14. Deduce...

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Answer 1

Answer #1

Degree of unsaturation = C-H/2 +1 = 6-14/2 + 1 = 0

Thus, molecule us acyclic and don't have any double bond.

Only two oeaks are obtained thus only two types of hydrogens are present in molecule.

Since, doublet for 12 H is obtained thus, molecule have symmetry in which these 12H have only one neighbouring H.

The only Possible structure is :

CM-CH CH-CM Scanned with CS CamScanner

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Answer 2

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